SOLUTION: Find the equation of the circle (in general form) tangent to the line 4x + 5y = 7 and concentric with the circle. (x-4)^2 +y^2 -5=0

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Question 1047542: Find the equation of the circle (in general form) tangent to the line 4x + 5y = 7 and concentric with the circle. (x-4)^2 +y^2 -5=0
Answer by ikleyn(52855) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the equation of the circle (in general form) tangent to the line 4x + 5y = 7 and concentric with the circle. (x-4)^2 +y^2 -5=0
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The center of the circle (of both circles) is at the point (4,0).


Find the distance from the point (4,0) to the straight line 4x + 5y = 7.
For it, use the formula for the distance from the point to the straight line in a coordinate plane

(for example, from the lesson The distance from a point to a straight line in a coordinate plane in this site).

d = abs%284%2A4+%2B+5%2A0+-7%29%2Fsqrt%284%5E2%2B5%5E2%29 = 9%2Fsqrt%2841%29.

    (Do not miss "d" with the diameter! In opposite, the "d" is the radius:

        r = 9%2Fsqrt%2841%29,  and  r%5E2 = 81%2F41. )

Now the equation of the circle is 

    %28x-4%29%5E2+%2By%5E2 = 81%2F41.




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