Question 1047311: Two circles, each of radius 14cm, are drawn with their centres 20cm apart. Find the exact length of their common chord.
How am I supposed to draw this? thanks.
Found 3 solutions by ikleyn, Boreal, josgarithmetic:
Answer by ikleyn(52937)   (Show Source):
Answer by Boreal(15235)  (Show Source):
You can put this solution on YOUR website! 
The chord has a positive and a negative part on the y-axis, and they are equal Each of those is a leg of a right triangle. The other leg is 10 cm along the x-axis. The hypotenuse is the radius or 14 cm. Therefore, the chord is x^2, one leg is 10^2=14^2, the hypotenuse.
x^2+100+196
x^2=96
x=4 sqrt(6) cm.
The length of the chord is 8 sqrt (6) units
Answer by josgarithmetic(39631)  (Show Source):
You can put this solution on YOUR website! The circle may overlap or intersect. How to draw this? DRAW THIS. You have the description and it's not too bad. Here is an attempt to show something like it on a cartesian system:
Of course, the graph here fails to display perfectly because the half-circles should be shown to intersect the x-axis. The equations for the circles represented here would be  .
You are looking for the two intersection points of the circles. These will occur for the SAME x value. Solving the two equations for x^2, and then equating the expressions will allow to find both values for y. THAT should help you well.
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