SOLUTION: Pic: http://d2vlcm61l7u1fs.cloudfront.net/media%2F057%2F0577453d-e7fa-4e47-9a92-eb814a082e46%2FphpRgQkvr.png IJ is the midsegment of trapezoid EFGH. Circle the following item w

Algebra ->  Points-lines-and-rays -> SOLUTION: Pic: http://d2vlcm61l7u1fs.cloudfront.net/media%2F057%2F0577453d-e7fa-4e47-9a92-eb814a082e46%2FphpRgQkvr.png IJ is the midsegment of trapezoid EFGH. Circle the following item w      Log On


   

Question 1039465: Pic: http://d2vlcm61l7u1fs.cloudfront.net/media%2F057%2F0577453d-e7fa-4e47-9a92-eb814a082e46%2FphpRgQkvr.png
IJ is the midsegment of trapezoid EFGH. Circle the following item which is always true.
(A)∠E≅∠F (B)HG+IJ=EF
(C)(line)IJ||(line)HG (D) HF=EG

If EF = 12, IJ = 3x-4, and HG = x, find lengths IJ and HG
IJ=__________
HG=__________

Thanks so much for your help.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Statement C is the only statement that is true for all quadrilaterals with at least one pair of parallel sides.

John

My calculator said it, I believe it, that settles it