SOLUTION: Find the equation of the circle which passes through (0,0), r=13 and the abscissa of its center is -12

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Question 1038686: Find the equation of the circle which passes through (0,0), r=13 and the abscissa of its center is -12
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
So the general equation of a circle is,
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
So we know,
R=13
k=-12
Substituting,
%28x-h%29%5E2%2B%28y%2B12%29%5E2=169
Using the point,
%280-h%29%5E2%2B%280%2B12%29%5E2=169
h%5E2%2B144=169
h%5E2=25
h=0+%2B-+5
There are two solutions,
%28x-5%29%5E2%2B%28y-12%29%5E2=169
and
%28x%2B5%29%5E2%2B%28y-12%29%5E2=169
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