SOLUTION: A sector of a circle of radius 8cm subtends an angle 90 degrees at the centre of the circle. If the sector is folded without overlap to form the curved surface of a cone, find the

Algebra ->  Circles -> SOLUTION: A sector of a circle of radius 8cm subtends an angle 90 degrees at the centre of the circle. If the sector is folded without overlap to form the curved surface of a cone, find the       Log On


   

Question 1028461: A sector of a circle of radius 8cm subtends an angle 90 degrees at the centre of the circle. If the sector is folded without overlap to form the curved surface of a cone, find the base radius, height and volume of the cone taking pie as 22/7
Answer by stanbon(75887) About Me  (Show Source):
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A sector of a circle of radius 8cm subtends an angle 90 degrees at the centre of the circle. If the sector is folded without overlap to form the curved surface of a cone, find the base radius, height and volume of the cone taking pie as 22/7
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Perimeter of the circle 16pi
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Perimeter of the base of the cone:: (3/4)16pi = 12pi
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height of cone::
radius of base of cone:: 12pi/(2pi) = 6
h^2 = 8^2 - 6^2 = 64-36 = 28
h = sqrt(28)
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volume of cone:: (1/3)pi*r^2*h = (1/3)pi*36*
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Cheers,
Stan H.
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