SOLUTION: Hello, could someone please help me with writing an equation? I have a graph with points A(1,-1) B(5,5) and a slope ofline k is -2/3. I am supposed to write the equation of line

Algebra ->  Points-lines-and-rays -> SOLUTION: Hello, could someone please help me with writing an equation? I have a graph with points A(1,-1) B(5,5) and a slope ofline k is -2/3. I am supposed to write the equation of line       Log On


   



Question 1025486: Hello, could someone please help me with writing an equation? I have a graph with points A(1,-1) B(5,5) and a slope ofline k is -2/3. I am supposed to write the equation of line k(6,0)(0,4) in standard form (Ax+By=C). I had the equation in slope-intercept form as y=-2/3x+4. When I take this equation and put in standard form, is the answer 2/3x+y=4 or is it 2x+3y=12? I appreciate any help!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The line through (6,0) and (0,4) is y=-%282%2F3%29x%2B4
Standard form has integer coefficients (x coefficient is positive).
3y=-2x%2B12
highlight_green%282x%2B3y=12%29
or
highlight%282x%2B3y-12=0%29