SOLUTION: Find the slope of a line tangent to the circle with a center (8,-7) and intersects at point (5,-5).

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Question 1024052: Find the slope of a line tangent to the circle with a center (8,-7) and intersects at point (5,-5).
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find the line connecting the center of the circle and the point of intersection.
The tangent line is perpendicular to this line.
First find the slope,
m=%28-5-%28-7%29%29%2F%285-8%29=2%2F%28-3%29=-2%2F3
Perpendicular lines have slopes that are negative reciprocals,
%28-2%2F3%29%2Am%5B2%5D=-1
m%5B2%5D=3%2F2
Using the point slope form,
y-%28-5%29=%283%2F2%29%28x-5%29
y%2B5=%283%2F2%29x-15%2F2
y=%283%2F2%29x-15%2F2-10%2F2
y=%283%2F2%29x-25%2F2
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