SOLUTION: The areas of the sides of a rectangular box are 12 in. squaredin.2​, 24 in. squaredin.2​, and 32 in .2. What is the volume of the​ box?

Algebra ->  Points-lines-and-rays -> SOLUTION: The areas of the sides of a rectangular box are 12 in. squaredin.2​, 24 in. squaredin.2​, and 32 in .2. What is the volume of the​ box?      Log On


   



Question 1023100: The areas of the sides of a rectangular box are 12 in. squaredin.2​, 24 in. squaredin.2​, and 32 in .2. What is the volume of the​ box?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Let w = width in inches, h = height in inches, and l = length in inches.
Without loss of generality, let
wh = 12,
hl = 24, and
lw = 32.
The first two equations imply that 12%2Fw+=+24%2Fl
==> l = 2w ==> (2w)w = 32 after substitution into the 3rd equation.
==> w%5E2+=+16 ==> w = 4 inches.
==> l = 8 inches, and h = 3 inches.
Therefore the volume is 3*4*8 = 96 cubic inches.