Question 1022137: The centre of a circle is at (2,6) and a chord of this circle of length 24 unit is bisected at (-1,2).Find the radius of the circle.
Found 2 solutions by josgarithmetic, solver91311:
Answer by josgarithmetic(39630)   (Show Source):
You can put this solution on YOUR website! Try moving the center and the bisection point so that circle center is the origin. This puts the bisection point at (-3,-4). Now, rotate the segment having endpoints (0,0) and (-3,-4), so that the bisection point lies on the positive y-axis; meaning you need to know the distance from (0,0) to (-3,-4). The 24 unit chord is now parallel to the x-axis and perpendicular to the y-axis. The two x-component coordinates are at -12 and +12.
Can you follow and perform the strategy as described and continue?
Note, the distance from center to bisection point even using the original given data is  .
The bisection point is 5 units from circle's center.
You should be able to find either of two right triangles. The side lengths are 5, 12, and r. The radius of the circle is r. (Pythagorean Right Triangle Formula to finish).
Answer by solver91311(24713)  (Show Source):
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