SOLUTION: If one interior angle of a regular polygon of n sides is 42 degrees more than an exterior angle of a regular polygon with 20 sides, then n equals
a) 3
b) 5
c) 6
d) 8
e) 10
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-> SOLUTION: If one interior angle of a regular polygon of n sides is 42 degrees more than an exterior angle of a regular polygon with 20 sides, then n equals
a) 3
b) 5
c) 6
d) 8
e) 10
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Question 1016005: If one interior angle of a regular polygon of n sides is 42 degrees more than an exterior angle of a regular polygon with 20 sides, then n equals
a) 3
b) 5
c) 6
d) 8
e) 10
Show your work Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
Each exterior angle of a polygon with 20 sides
measures (360/20)=18 degrees. The sum of exterior
angles of all polygons is 360 degrees.
.
Interior angle of other polygon = 18 + 42 = 60 degrees
.
(n-2)/n(180)=60
(n-2)(180)=60n
180n-360=60n
120n-360=0
120n=360
n=3
.
ANSWER: A is correct, n=3
