SOLUTION: reduce -3x - 5y + 11 = 0 to normal form and give the distance of the line from the origin.

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Question 1014674: reduce -3x - 5y + 11 = 0 to normal form and give the distance of the line from the origin.
Answer by ikleyn(53763) About Me  (Show Source):
You can put this solution on YOUR website!
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reduce -3x - 5y + 11 = 0 to normal form and give the distance of the line from the origin.
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Normal form equation of this straight line is

3x + 5y = 11.

The distance of the line from the origin (0,0) is 


d = abs%283%2A0+%2B+5%2A0+-11%29%2Fsqrt%283%5E2+%2B+5%5E2%29 = 11%2Fsqrt%2834%29.


For details, see the lesson The distance from a point to a straight line in a coordinate plane in this site.