SOLUTION: Find the equation of each family of lines described. Identify three members of the family and sketch them. Perpendicular to the line 8x+y=6.

Algebra ->  Points-lines-and-rays -> SOLUTION: Find the equation of each family of lines described. Identify three members of the family and sketch them. Perpendicular to the line 8x+y=6.       Log On


   



Question 1011465: Find the equation of each family of lines described. Identify three members of the family and sketch them.
Perpendicular to the line 8x+y=6.

Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39623) About Me  (Show Source):
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
to find a line perpendicular to the line 8x%2By=6, write this equation in a slope-intercept form y=mx%2Bb where m is a slope and b is y-intercept
we will need a slope m because two lines are perpendicular if their slopes are negative reciprocal to each other
y=highlight%28-8%29x%2B6=>a slope m=-8
a line perpendicular to this line will have a slope m%5Bp%5D=-%281%2F-8%29=> m%5Bp%5D=%281%2F8%29
so,y=%281%2F8%29x is a line perpendicular to 8x%2By=6
for each line we need two points to graph them
x|y....for 8x%2By=6
0|6........8%2A0%2By=6=>y=6
1|-2........8%2A%281%29%2By=6=>8%2By=6=>y=6-8=>y=-2

x|y....for y=%281%2F8%29x
0|0........y=%281%2F8%290=>y=0
8|1........y=%281%2F8%298=>y=1