SOLUTION: Graph a line that passes through H(8,5) and is perpendicular to AG with A(-5,6) and G(-1,-2)

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Question 1009898: Graph a line that passes through H(8,5) and is perpendicular to AG with A(-5,6) and G(-1,-2)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Slope of AG is %286-%28-2%29%29%2F%28-5-%28-1%29%29=8%2F-4=-2;
The slope of any line perpendicular to AG is 1%2F2, which is the negative reciprocal of -2.

If you just want to graph the line asked for, you have the given point H (8,5). Plot H, and use the slope of 1%2F2 to find other points, and then draw the line through these points.

y-5=%281%2F2%29%28x-8%29------applying the point-slope formula
y-5=x%2F2-4
y=x%2F2%2B5-4
y=x%2F2%2B1-------finishing equation in slope-intercept form

graph%28300%2C300%2C-4%2C8%2C-4%2C8%2Cx%2F2%2B1%29