SOLUTION: for what value of k does circle (x+2k)^2+(y-3k)^2=10 passes through point (1,0)

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Question 1008367: for what value of k does circle (x+2k)^2+(y-3k)^2=10 passes through point (1,0)
Answer by MathLover1(20850) About Me  (Show Source):
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for what value of k does circle %28x%2B2k%29%5E2%2B%28y-3k%29%5E2=10 passes through point (1,0)
substitute 1 for x and 0 for y
%281%2B2k%29%5E2%2B%280-3k%29%5E2=10
1%2B4k%2B4k%5E2%2B9k%5E2=10
13k%5E2%2B4k%2B1-10=0
13k%5E2%2B4k-9=0
13k%5E2%2B13k-9k-9=0
%2813k%5E2%2B13k%29-%289k%2B9%29=0
13k%28k%2B1%29-9%28k%2B1%29=0
%2813k-9%29%28k%2B1%29=0
solutions:
13k-9=0 => 13k=9 => k=9%2F13
k%2B1=0 => k=-1