SOLUTION: What point lies on the graph of the circle given by the equation: ( x - 2 )^2+( y+1)=36

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Question 973805: What point lies on the graph of the circle given by the equation: ( x - 2 )^2+( y+1)=36
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What point lies on the graph of the circle given by the equation: ( x - 2 )^2+( y+1)=36
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Center:: (2,-1)
radius = sqrt(36) = 6
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Ans: 6 to the left of (2,-1) is the point (-4,-1)
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Cheers,
Stan H.
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