SOLUTION: Find the points of intersection of the graphs of x^2+y^2=25 and y=3x-3 Thanks!

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Question 633738: Find the points of intersection of the graphs of x^2+y^2=25 and y=3x-3
Thanks!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Find the points of intersection of the graphs:

y=3x-3 

x^2+y^2=25

x^2 + (3x-3)^2 = 25

 10x^2 - 18x -16 = 0

  5x^2 - 9x -8 = 0

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%289+%2B-+sqrt%28+241%29%29%2F%2810%29+

  x = 2.45  or x = -.65

 points of intersection of the graphs: (2.45, 4.35)  and (-.65, -4.96)