SOLUTION: I dont understand how you would reflect a point over y = -1. My problem is: If Q (3, 4) of triangle QRS is translated by reflecting it about the graph of y = -1, what are the coord

Algebra ->  Points-lines-and-rays -> SOLUTION: I dont understand how you would reflect a point over y = -1. My problem is: If Q (3, 4) of triangle QRS is translated by reflecting it about the graph of y = -1, what are the coord      Log On


   

Question 308237: I dont understand how you would reflect a point over y = -1. My problem is: If Q (3, 4) of triangle QRS is translated by reflecting it about the graph of y = -1, what are the coordinates of Q'?
How do you do this?
~betsy
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
y = -1 is a horizontal line ___ reflection is PERPENDICULAR to the line of reflection

so the horizontal component, x, of the point doesn't change

the y component of the point is 5 units (4 - -1) ABOVE the line of reflection
___ so the reflected value will be 5 units BELOW the line of reflection

so ___ Q' is (3, -6)