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Question 307590: what is the acute angle between lines 4x-3y=6 and 4x-y=10?
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! what is the acute angle between lines 4x-3y=6 and 4x-y=10?
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Find the slope, m, of each line. The slope is the tangent of the angle with the x-axis.
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4x-3y=6
m1 = 4/3
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4x-y=10
m2 = 4
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Angle = arctan(m2) - arctan(m1) = arctan(4) - arctan(4/3)
= 75.964 - 53.13 degs
=~ 22.8337º
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There's a vector method, also.
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