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Question 206927This question is from textbook New Syllabus Mathematics D Book 4
: I donot know whether to put this question on this department or in the others. If you know where to submit the question please let me know. Anyways the question is the following;
Kindly, help me solve this question it is urgent!
I have never solved this type of question.
A wheel of radius 40cm is turning about a fixed axis through the centre of the wheel at acentre rate of 2 revolutions per minute. Calculate the
(a) Angle through which the wheel turns in 10 seconds.
(b) Distance moved by a point on the rim in 10 seconds.
I hope someone will solve it. I shall be highly obliged to you.
Thanks,
This question is from textbook New Syllabus Mathematics D Book 4

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
The wheel completes a full revolution in 2 seconds. A full revolution means the wheel turns through 360 degrees.
1) IN 10 seconds, the wheel will make 10seconds%2F2revpersecond+=+5revolutions
If each revolution is 360, then the total angle is 5%2A360+=+1800 degrees
2) You know the wheel makes 5 revolutions. If you take your finger, place it on a point on the circumference of the circle and then trace a full revolutuion, you end up back at the same point. The length of the circumference of a circle is given by C+=+2%2Api%2Ar
So C+=+2%2Api%2A40+=+80%2Api
That is the distance made on a single revolution. This circle makes 5 revolutions, so the Distance+=+5+%2A+80+%2A+pi+=+400%2Api