SOLUTION: πΈ is the midpoint of π·F. π·πΈ = 4π₯ + 3
and πΈπΉ = 8π₯ β 9. Find π·πΈ, πΈπΉ, and π·οΏ½
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-> SOLUTION: πΈ is the midpoint of π·F. π·πΈ = 4π₯ + 3
and πΈπΉ = 8π₯ β 9. Find π·πΈ, πΈπΉ, and π·οΏ½
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Question 1203782: πΈ is the midpoint of π·F. π·πΈ = 4π₯ + 3
and πΈπΉ = 8π₯ β 9. Find π·πΈ, πΈπΉ, and π·οΏ½ Found 2 solutions by mananth, MathLover1:Answer by mananth(16946) (Show Source):
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πΈ is the midpoint of π·F. π·πΈ = 4π₯ + 3
and πΈπΉ = 8π₯ β 9. Find π·πΈ, πΈπΉ, and π·
Since e is the midpoint of DF DE = EF
Therefore 4x+3 = 8x-9
subtract 8x from both sides of equation
4x+3-8x = -9
substract 3 from both sides
4x -8x = -9-3
-4x = -12
x = -12/-4=3
DE = 4x+3
plug x
DE = 4*3+3
DE = 15
Therefore EF = 15
