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Question 1105675: What is an equation of the line with y-intercept -15 and is perpendicular to the line whose equation is y=1/3+6
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website! What is an equation of the line with y-intercept -15 and is perpendicular to the line whose equation is y=1/3+6
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NOTE:
Assuming the equation of the given line was intended to be written
y = (1/3)x + 6 (there is no x in the original problem statement)
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Slope-intercept form is: y = mx + b (m=slope, b= y-axis intercept)
We know straight away that b=-15 as the problem asks for that.
As for m, two lines are perpendicular when m1 = -1/m2. Since the given
line has slope (1/3), the slope we want for the perpendicular line is -1/(1/3) = -3.
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Ans: y = -3x -15
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