SOLUTION: I am trying to write an equation on the line parallel to y=8x-1 that contains (-6,2). How do I do it?

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Question 1099368: I am trying to write an equation on the line parallel to y=8x-1 that contains (-6,2). How do I do it?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
y=8x-1, shows slope is 8, so any line parallel will also have slope of 8.

y=mx%2Bb
y-mx=b
b=y-mx
point must include (-6,2);
b=2-8%28-6%29
b=2%2B48
b=50

Line Equation Wanted: highlight%28y=8x%2B50%29

Answer by greenestamps(13195) About Me  (Show Source):
You can put this solution on YOUR website!

Every line parallel to the line with equation y=8x-1 will have an equation of the general form y = 8x+k, where k is some constant.

To find the particular line that is parallel to the given line and passes through a particular point, plug the x and y value of that point into the general form and solve for k:

y+=+8x+%2B+k
2+=+8%28-6%29%2Bk
2+=+-48%2Bk
50+=+k

The equation you are looking for is y+=+8x%2B50