SOLUTION: find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x-6y=9 and passing through (-2,-1).

Algebra ->  Points-lines-and-rays -> SOLUTION: find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x-6y=9 and passing through (-2,-1).      Log On


   

Question 108243: find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x-6y=9 and passing through (-2,-1).
Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
the given equation is:

3x - 6y = 9

Writing this equation in the slope intercept form, we get:


y+=+%28x%2F2%29+-+%283%2F2%29

therefore the slope in the above equation is m = (1/2)

We know that 2 lines are perpendicular when the product of their slopes are equal to -1.

So the slope of the second line is = -2

Now substituing the point and the slope in the one point form we get the required line.

(y - y1) = m(x - x1)

(y - (-1)) = (-2)(x - (-2))

y + 1 = (-2)( x + 2)

y + 1 = -2x - 4

==> y = -2x - 5

thus the required line