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Question 1052371: Write the equation of the line that contains the indicated points and meets the indicated conditions. Passing thru: (-2,1)
a) parallel to 2x+3y=5 b) perpendicular to 2x-3y=5
Answer by josgarithmetic(39615)   (Show Source):
You can put this solution on YOUR website! Parallel to 2x+3y=5, will have the same slope, which if solve for y in terms of x and look at coefficient on x, is  . Such line to pass through the given point, using point-slope form, is  .
Perpendicular to 2x-3y=5, will have a slope negative reciprocal of that for this given line. Solve this given equation for y in terms of x, take the negative reciprocal of coefficient on x, and it will be  . The line passing through the given point with this slope is, in point-slope form,  .
converting between point-slope and slope-intercept forms
That should help you see how to also understand the standard form Ax+By=C. You CAN find the slope if you learn how to read this form of equation.
The work I described and did, could be done all in standard form, if you learn to read and use the standard form equation.
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