SOLUTION: A circle has center in the third quadrant, the first coordinate of its center is −4 , and is tangent to the lines ℓ1:x=4 and ℓ2:y=4 . The center of

Algebra ->  Circles -> SOLUTION: A circle has center in the third quadrant, the first coordinate of its center is −4 , and is tangent to the lines ℓ1:x=4 and ℓ2:y=4 . The center of       Log On


   



Question 963873: A circle has center in the third quadrant, the first coordinate of its center is −4 , and is tangent to the lines ℓ1:x=4 and ℓ2:y=4 .

The center of the circle is at the point C:(__,__) , and the circle has radius r=___.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
With the center at x=-4, the distance to x=4 is 4-%28-4%29=8.
So the radius of the circle is 8.
So then the distance from the y-center to the line y=4 is the same distance.
4-y%5Bc%5D=8
y%5Bc%5D=-4
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(-4,-4)
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