SOLUTION: This is the fourth time I've submitted this question because I keep entering it in wrong!! I need help solving these equations. I keep getting (sqrt of 2, 2* sqrt of two) and (i s

Algebra ->  Circles -> SOLUTION: This is the fourth time I've submitted this question because I keep entering it in wrong!! I need help solving these equations. I keep getting (sqrt of 2, 2* sqrt of two) and (i s      Log On


   

Question 920784: This is the fourth time I've submitted this question because I keep entering it in wrong!!
I need help solving these equations. I keep getting (sqrt of 2, 2* sqrt of two) and (i sqrt of two, 2i*sqrt of two)
+x%5E2+%2B+y%5E2+=+10+
y= 2x
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Simply substitute for y and first solve for x.

x%5E2%2B%282x%29%5E2=10
x%5E2%2B4x%5E2=10
5x%5E2=10
x%5E2=10%2F5
x%5E2=2
highlight%28x=-sqrt%282%29%29 OR highlight%28x=sqrt%282%29%29


When highlight%28x=-sqrt%282%29%29, y=2%2Ax=2%28-sqrt%282%29%29=highlight%28-2sqrt%282%29=y%29.

When highlight%28x=sqrt%282%29%29, highlight%28y=2sqrt%282%29%29.