SOLUTION: Find the points of intersection of the circles: x^2 + y^2-2x-2y-2=0 and x^2+y^2+2x+2y-2=0. Draw the circles

Algebra ->  Circles -> SOLUTION: Find the points of intersection of the circles: x^2 + y^2-2x-2y-2=0 and x^2+y^2+2x+2y-2=0. Draw the circles      Log On


   

Question 893015: Find the points of intersection of the circles: x^2 + y^2-2x-2y-2=0 and x^2+y^2+2x+2y-2=0. Draw the circles
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + y^2-2x-2y-2=0 and x^2+y^2+2x+2y-2=0

x%5E2+%2B+y%5E2-2x-2y-2=0
x%5E2-2x%2By%5E2-2y-2=0
x%5E2-2x%2B1-1%2By%5E2-2y%2B1-1-2=0
%28x-1%29%5E2%2B%28y-1%29%5E2-4=0
highlight_green%28%28x-1%29%5E2%2B%28y-1%29%5E2=4%29


x%5E2%2By%5E2%2B2x%2B2y-2=0
x%5E2%2B2x%2By%5E2%2B2y-2=0
x%5E2%2B2x%2B1-1%2By%5E2%2B2y%2B1-1-2=0
%28x%2B1%29%5E2%2B%28y%2B1%29%5E2-4=0
highlight_green%28%28x%2B1%29%5E2%2B%28y%2B1%29%5E2=4%29

The symmetry of this system indicates that intersections should occur on the line y=-x.



(-1,1) and (1,-1) work as the intersections.