SOLUTION: What is the correct standard equation of a circle with center (5, -1) and radius 12?
a
(x + 5)2 + (y - 1)2 = 144
b
(x + 5)2 + (y - 1)2 = 12
c
(x – 5)2 + (y + 1)2 = 1
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Circles
-> SOLUTION: What is the correct standard equation of a circle with center (5, -1) and radius 12?
a
(x + 5)2 + (y - 1)2 = 144
b
(x + 5)2 + (y - 1)2 = 12
c
(x – 5)2 + (y + 1)2 = 1
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Question 876334: What is the correct standard equation of a circle with center (5, -1) and radius 12?
a
(x + 5)2 + (y - 1)2 = 144
b
(x + 5)2 + (y - 1)2 = 12
c
(x – 5)2 + (y + 1)2 = 144
d
(x – 5)2 + (y + 1)2 = 12 Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! circle with center (5, -1) and radius 12
c. (x – 5)^2 + (y + 1)^2 = 144
Need to Know
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius
