SOLUTION: please help me solve this equation ; the circle is divided into 4 parts a,b,c,d where part a & c form a semicircle and part b&d form the other semicircle area of part a to area of

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Question 746229: please help me solve this equation ; the circle is divided into 4 parts a,b,c,d where part a & c form a semicircle and part b&d form the other semicircle area of part a to area of part c is in the ratio 1: 3 the area of part b to the area of part d is in the ratio 1:2. the area of part c is bigger than part b by 20 SquareCentimeters find the area of the whole cirle
Answer by savvyhush23(50) About Me  (Show Source):
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please help me solve this equation ; the circle is divided into 4 parts a,b,c,d where part a & c form a semicircle and part b&d form the other semicircle area of part a to area of part c is in the ratio 1: 3 the area of part b to the area of part d is in the ratio 1:2. the area of part c is bigger than part b by 20 SquareCentimeters find the area of the whole cirle.
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Ok, let solve it one by one,
Let,
At = Total area of circle
Aa = Area of a
Ab = Area of b
Ac = Area of c
Ad = Area of d
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part a & c form a semicircle...part b&d form the other semicircle:
At%2F2+=+Aa+%2B+Ac, and At%2F2+=+Ab+%2B+Ad
part a to area of part c is in the ratio 1:3...Aa%2FAc=1%2F3, or Ac=3Aa
part b to the area of part d is in the ratio 1:2...Ab%2FAd=1%2F2, or Ad=2Ab
the area of part c is bigger than part b by 20...Ac+=+Ab+%2B+20
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Ok, here is my favorite part:
We have 5 unknown (At, Aa, Ab, Ac, and Ad), so we have to form 5 equations to solve it. The 4 equations are ready above,
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since a & c and b & d are semi circle, At%2F2=At%2F2, equation 5
we have the 2 equations for that above, substituting here, Aa+%2B+Ac+=+Ab+%2B+Ad, or -Aa+%2B+Ab+-+Ac+%2B+Ad+=+0, then add this to the other 3 remaining equation:
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but +Aa+=+Ac%2F3 and Ab=Ac-20, so, 2%28Ac%2F3%29+%2B+2%28Ac-20%29-+Ac+-+20=0,
So, Ac+=+36+cm%5E2, Ab+=+16+cm%5E2, Ad=32+cm%5E2, and Aa=12+cm%5E2
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Therefore, At+=+Aa+%2B+Ab+%2B+Ac+%2B+Ad+=+96+cm%5E2
Check it, the value of individual area must satisfy the given ratio.