SOLUTION: Solve the system algebraically. x^2+y^2+2x+4y-8=0 3x+2y=6 I wasn't really sure how to solve this so I started, but I sort of got stuck... 2y=-3x+6 y=-(3/2)x+3 x^2+(-3/2x+

Algebra ->  Circles -> SOLUTION: Solve the system algebraically. x^2+y^2+2x+4y-8=0 3x+2y=6 I wasn't really sure how to solve this so I started, but I sort of got stuck... 2y=-3x+6 y=-(3/2)x+3 x^2+(-3/2x+      Log On


   

Question 695812: Solve the system algebraically.
x^2+y^2+2x+4y-8=0
3x+2y=6
I wasn't really sure how to solve this so I started, but I sort of got stuck...
2y=-3x+6
y=-(3/2)x+3
x^2+(-3/2x+3)^2+2x+4(-3/2x+3)-8=0
...then I got stuck.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
You're not that far from the solution:
x%5E2%2B%28%28-3%2F2%29x%2B3%29%5E2%2B2x%2B4%28%28-3%2F2%29x%2B3%29-8=0
x%5E2%2B%28%289%2F4%29x%5E2-9x%2B9%29%2B2x%2B%28-6x%2B12%29-8=0
x%5E2%2B%289%2F4%29x%5E2-9x%2B9%2B2x-6x%2B12-8=0
%281%2B%289%2F4%29%29x%5E2%2B%28-9%2B2-6%29x%2B9%2B12-8=0
%2813%2F4%29x%5E2%2B%28-13%29x%2B13=0
%2813%2F4%29x%5E2-13x%2B13=0
%281%2F4%29x%5E2-x%2B1=0
x%5E2-4x%2B4=0
%28x-2%29%5E2=0
highlight%28x=2%29
y=%28-3%2F2%29%282%29%2B3
y=-3%2B3
highlight%28y=0%29