SOLUTION: I need to know: How would i convert (x^2+y^2+2x-10=0) into (x-h)^2+(y-k)^2=r^2 format? I needed to find the radius and the center of the equation.
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-> SOLUTION: I need to know: How would i convert (x^2+y^2+2x-10=0) into (x-h)^2+(y-k)^2=r^2 format? I needed to find the radius and the center of the equation.
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Question 68730: I need to know: How would i convert (x^2+y^2+2x-10=0) into (x-h)^2+(y-k)^2=r^2 format? I needed to find the radius and the center of the equation. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! convert (x^2+y^2+2x-10=0) into (x-h)^2+(y-k)^2=r^2 format
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You need to "complete the square" on the x terms and separately
on the y terms, as follows:
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(x^2+2x+1) + (y^2) = 10+1
(x+1)^2 + (y-0)^2 = [sqrt(11)]^2
Center is at (-1,0)
Radius is sqrt(11)
Cheers,
Stan H.
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