SOLUTION: If P is a point on the circle x2+y2=9 and Q is a point on the line 7x+y+3=0 and the line is perpendicular bisector of line PQ, find the coordinet of P.
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-> SOLUTION: If P is a point on the circle x2+y2=9 and Q is a point on the line 7x+y+3=0 and the line is perpendicular bisector of line PQ, find the coordinet of P.
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Question 681863: If P is a point on the circle x2+y2=9 and Q is a point on the line 7x+y+3=0 and the line is perpendicular bisector of line PQ, find the coordinet of P.
You can put this solution on YOUR website! I believe something is wrong or missing.
Otherwise it would be sort of a trick question.
Lines do not have bisectors; only segments do.
A perpendicular bisector of segment (not line) PQ is a line that goes through the midpoint of segment PQ, and is perpendicular to PQ.
If Q is a point on the line that is the perpendicular bisector of line PQ, then P, Q, and the midpoint of PQ would all be the same point.
That point would belong to the circle (because it is P), and to the line (because it is Q).
P and Q would be (0,-3) or (-42/50,144/50)
