SOLUTION: What is the center and radius of (x-3)^2+(y-1)^2=36?

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Question 648986: What is the center and radius of (x-3)^2+(y-1)^2=36?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
the general formula of the circle is %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 where +h and k are the x and y coordinates of the center of the circle , and r is the radius
you are given %28x-3%29%5E2%2B%28y-1%29%5E2=36
if you compare your equation to the general formula of the circle, you can see that h=3 and k=1;so, the center is at (3,1)
and r%5E2=36...->... r=6

Solved by pluggable solver: PLOT any circle and describe it

Diameter: d+=+2r+=+2%2A6+=+12.
Area: area+=+pi%5Cr%5E2+=+pi%2A6%5E2+=+113.097336983618
Perimeter: perimeter+=+2%5Cpi%5Cr+=+2%5Cpi%2A6+=+37.6991123278728