SOLUTION: Here is a tiring problem. The diameter of a car tire is approximately 60 centimeters. The warranty is good for 70,000 km. About how many revolutions will the tire make before th

Algebra ->  Circles -> SOLUTION: Here is a tiring problem. The diameter of a car tire is approximately 60 centimeters. The warranty is good for 70,000 km. About how many revolutions will the tire make before th      Log On


   

Question 58977This question is from textbook discovering geometry- an investigative approach
: Here is a tiring problem. The diameter of a car tire is approximately 60 centimeters. The warranty is good for 70,000 km. About how many revolutions will the tire make before the warranty is up? More than a million? A billion? This question is from textbook discovering geometry- an investigative approach

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Here is a tiring problem. The diameter of a car tire is approximately 60 centimeters. The warranty is good for 70,000 km. About how many revolutions will the tire make before the warranty is up? More than a million? A billion
Find the circum of the tire: C = pi*60 = 188.5 cm, or write it 1.885(10^2)
:
Theres 100,000 cm in 1 km, call it 10^5 cm
:
70000 is 7(10^4)
:
7(10^4) * (10^5) = 7(10^9) cm in 70,000 km
:
7%2810%5E9%29%2F1.885%2810%5E2%29 = 3.71(10^7) which is 37.1 million