SOLUTION: Consider the circle x^2+y^2-6x-8y=0 Find the center and radius of the circle

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Question 481180: Consider the circle x^2+y^2-6x-8y=0
Find the center and radius of the circle
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

where Pt(h,k) is the center and r is the radius.

x^2+y^2-6x-8y=0   |completing the Squares

(x-3)^2 + (y-4)^2 = 9+16

%28x-3%29%5E2+%2B+%28y-4%29%5E2+=+25