SOLUTION: Find the equation of the circle that has its center at (6,-5) and passes through (1,7).

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Question 413503: Find the equation of the circle that has its center at (6,-5) and passes through (1,7).
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!



Hi

Find the equation of the circle that has its center at (6,-5) and passes through (1,7).

(6,-5)

(1,7)

 r = sqrt(5^2 + (-12)^2) = 13      |D = sqrt+%28%28x1-x2%29%5E2%2B%28y1-y2%29%5E2%29%29

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

where Pt(h,k) is the center and r is the radius



   (x-6)^2 + (y+5)^2 = 169