SOLUTION: I need help on finding the center and radius in general form on 9x^2+9y^2-6y-17=0. And i would like to see it completely broke down step-by-step. As far as I got was (9x^2+ )+(9y

Algebra ->  Circles -> SOLUTION: I need help on finding the center and radius in general form on 9x^2+9y^2-6y-17=0. And i would like to see it completely broke down step-by-step. As far as I got was (9x^2+ )+(9y      Log On


   

Question 178990This question is from textbook
: I need help on finding the center and radius in general form on 9x^2+9y^2-6y-17=0. And i would like to see it completely broke down step-by-step. As far as I got was (9x^2+ )+(9y^2-6y+ )=0. I don't understand how you find the other numbers. This question is from textbook

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
ok we need to complete the square with the y terms
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9x%5E2%2B9y%5E2-6y-17=0.given
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9%28y%5E2-%282%2F3%29y%2B1%2F9%29%2B9x%5E2-17-9=0setting up for completing square.factored out a 9 from the terms 9y%5E2-6y added and subtracted 1/9 so as to complete the square and keep the equation equivilent.
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9%28y-%281%2F3%29%29%5E2%2B9x%5E2-17-1%2F9=0completed the square
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9%28y-%281%2F3%29%29%5E2%2B9x%5E2=154%2F9put in general form. changed mixed fraction -17 1/9 to improper fraction 154/9.
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center is (0,1/3), radius is sqrt%28154%2F9%29=sqrt%28154%29%2F3
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