SOLUTION: A. Find the center and radius of the circle.
B. Graph the circle.
C. Find the intercepts of the circle, if any.
3x^2 + 3y^2 - 12y = 0
Algebra ->
Circles
-> SOLUTION: A. Find the center and radius of the circle.
B. Graph the circle.
C. Find the intercepts of the circle, if any.
3x^2 + 3y^2 - 12y = 0
Log On
3x^2 + 3y^2 - 12y = 0
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x^2 + y^2 - 4y = 0
x^2 + y^2 - 4y + 4 = 4
(x-0)^2 + (y-2)^2 = 2^2
Center is (0,2)
r = 2
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You can graph it on paper, or
DL the FREE graph software from several sites.
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x^2 + y^2 - 4y = 0
Sub zero for x to find the y-intercepts
y^2 - 4y = 0
y*(y-4) = 0
y = 0 --> (0,0)
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y = 4 --> (0,4)
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Sub zero for y to find the x-intercepts
x^2 + y^2 - 4y = 0
x^2 = 0
--> (0,0)
