Question 1168236: Write the equation of a circle that satisfies the given conditions:
(a) the center is at (1, -3) and the circle passes through (-3, 5).
(b) the line segment joining A (0, 0), and B (6, -8) is a diameter.
(c) the circle is tangent to y-axis, and the center is at (5, 3)
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! Write the equation of a circle that satisfies the given conditions:
(a) the center is at (1, -3) and the circle passes through (-3, 5).
(b) the line segment joining A (0, 0), and B (6, -8) is a diameter.
(c) the circle is tangent to y-axis, and the center is at (5, 3)
(a) the center is at (1, -3) and the circle passes through (-3, 5).
Find radius by distance formula.
r= sqrt(80)
=4sqrt(5)
Now we have the radius, r, and the center (ℎ,k)~(1,-3) and radius 4sqrt(5)
We can plug these values into the general equation of a circle:
(x-1)^2+(y+3)^2= (4sqrt(5))^2
(x-1)^2+(y+3)^2= 80
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