SOLUTION: Suppose that we have a right triangle $ABC$ with the right angle at $B$ such that $AC = \sqrt{61}$ and $AB = 5.$ A circle is drawn with its center on $AB$ such that the circle is t
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-> SOLUTION: Suppose that we have a right triangle $ABC$ with the right angle at $B$ such that $AC = \sqrt{61}$ and $AB = 5.$ A circle is drawn with its center on $AB$ such that the circle is t
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Question 1088328: Suppose that we have a right triangle $ABC$ with the right angle at $B$ such that $AC = \sqrt{61}$ and $AB = 5.$ A circle is drawn with its center on $AB$ such that the circle is tangent to $AC$ and $BC.$ If $P$ is the point where the circle and side $AC$ meet, then what is $CP$? Answer by ikleyn(52797) (Show Source):
0. Make a sketch to follow my arguments.
Let O be the center of the circle located on the leg AB, and
P be the tangent point lying on the hypotenuse AC.
1. Two right-angled triangles are similar: triangle ABC and triangle APO.
2. Regarding the triangle ABC, notice that its sides are 5 (the leg AB), (the hypotenuse AC) and = = 6 (the other leg BC).
3. Let r be the unknown radius of the circle.
4. Use two proportions that follow the similarity of the triangles:
= ,
which after substituting the data takes the form
= .
From this point, can you complete the solution on your own ?
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