SOLUTION: Find the equation of the circle which passes through points (2,-2) and (3,4) and whose centre lies on the line x + y = 7
Algebra ->
Circles
-> SOLUTION: Find the equation of the circle which passes through points (2,-2) and (3,4) and whose centre lies on the line x + y = 7
Log On
Question 1065132: Find the equation of the circle which passes through points (2,-2) and (3,4) and whose centre lies on the line x + y = 7 Found 2 solutions by ikleyn, Alan3354:Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
Find the equation of the circle which passes through points (2,-2) and (3,4) and whose centre lies on the line x + y = 7
~~~~~~~~~~~~~~~~~~~~~~~~~~~
1. Find the equation of the straight line passing through the two given points.
2. Find the equation of the straight line perpendicular to that of the n.1 and passing through the midpoint between the two given point.
This straight line will be the perpendicular bisector.
3. Find the intersection of the line of n.2 and the straight line x + y = 7.
This intersection will be the center of the circle.
4. Find the distance from the center to either of the two given point.
5. Write the equation of the circle.
6. You are done ! My congratulations !!.
You can put this solution on YOUR website! Find the equation of the circle which passes through points (2,-2) and (3,4) and whose centre lies on the line x + y = 7
----------------
Find the equation of the line thru the 2 points.
The center of the circle in on the perpendicular bisector (PB) of that line.
---
Find the intersection of the PB and the line x + y = 7.
That's the center (h,k).
---
The radius r is the distance from the center to either point.
============ is the circle.
------------
email via the TY note for help or to check your work.
