SOLUTION: Points A,B,C,D and E are collinear arranged in that order such that the distance from A to E is 30 units, the distance from A to D is 25 units, the distance from B to E is 15 uni

Algebra ->  Points-lines-and-rays -> SOLUTION: Points A,B,C,D and E are collinear arranged in that order such that the distance from A to E is 30 units, the distance from A to D is 25 units, the distance from B to E is 15 uni      Log On


   



Question 1012986: Points A,B,C,D and E are collinear arranged in that order such that the distance from A to E is 30 units, the distance from A to D is 25 units, the distance from B to E is 15 units, and C is halfway between B and D. What is the distance from B to C?
Answer by Boreal(15235) About Me  (Show Source):
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A=================================E 30
A===========================D 25
================B=================E 15
=======================C
BE is 15 units, BD is 10 units
C is half way between B and D
B is at 15 units from A
D is 25 units from A
C must be at 20 units, half way between 15 and 25.
BC is 5 units.