SOLUTION: Determine the radius of the circle.(-11,6) Is the circumference of the circle and (-5,2) is the center of the circle. Could you please write the standard equations for this.

Algebra ->  Circles -> SOLUTION: Determine the radius of the circle.(-11,6) Is the circumference of the circle and (-5,2) is the center of the circle. Could you please write the standard equations for this.      Log On


   



Question 970532: Determine the radius of the circle.(-11,6) Is the circumference of the circle and (-5,2) is the center of the circle. Could you please write the standard equations for this.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2
Determine the radius of the circle.
(-11,6) Is the circumference of the circle => (-11,6) could be only one point on the circle
if (-5,2) is the center of the circle and and (-11,6) one point on the circle, then radius is the distance (d=r) between the center and the point
use distance formula to find the radius:
Solved by pluggable solver: Distance Formula


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-11, 6), we can say (x1, y1) = (-11, 6)
So x%5B1%5D+=+-11, y%5B1%5D+=+6


Since the second point is (-5, 2), we can also say (x2, y2) = (-5, 2)
So x%5B2%5D+=+-5, y%5B2%5D+=+2


Put this all together to get: x%5B1%5D+=+-11, y%5B1%5D+=+6, x%5B2%5D+=+-5, and y%5B2%5D+=+2

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Now use the distance formula to find the distance between the two points (-11, 6) and (-5, 2)



d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29


d+=+sqrt%28%28-11+-+%28-5%29%29%5E2+%2B+%286+-+2%29%5E2%29 Plug in x%5B1%5D+=+-11, y%5B1%5D+=+6, x%5B2%5D+=+-5, and y%5B2%5D+=+2


d+=+sqrt%28%28-11+%2B+5%29%5E2+%2B+%286+-+2%29%5E2%29


d+=+sqrt%28%28-6%29%5E2+%2B+%284%29%5E2%29


d+=+sqrt%2836+%2B+16%29


d+=+sqrt%2852%29


d+=+sqrt%284%2A13%29


d+=+sqrt%284%29%2Asqrt%2813%29


d+=+2%2Asqrt%2813%29


d+=+7.21110255092798

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Answer:


The distance between the two points (-11, 6) and (-5, 2) is exactly 2%2Asqrt%2813%29 units


The approximate distance between the two points is about 7.21110255092798 units



So again,


Exact Distance: 2%2Asqrt%2813%29 units


Approximate Distance: 7.21110255092798 units




so, in formula for a circle we need radius squared and it is r=52
then, from the coordinates of the center we know that h=5 and k=-2 and your standard formula is:
%28x-5%29%5E2%2B%28y%2B2%29%5E2=52