SOLUTION: I have a circle whose radius increases 2.2' per hour, starting from 0. I have determined that the area of the circle is 60.82' sq after 2 hrs. How do I represent the area as a func

Algebra ->  Circles -> SOLUTION: I have a circle whose radius increases 2.2' per hour, starting from 0. I have determined that the area of the circle is 60.82' sq after 2 hrs. How do I represent the area as a func      Log On


   



Question 321270: I have a circle whose radius increases 2.2' per hour, starting from 0. I have determined that the area of the circle is 60.82' sq after 2 hrs. How do I represent the area as a function of time???
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I have a circle whose radius increases 2.2' per hour, starting from 0. I have determined that the area of the circle is 60.82' sq after 2 hrs. How do I represent the area as a function of time???
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Area = pi*r^2
r = 2.2t
Area = pi*4.84t^2
= 2.5963t^2