SOLUTION: A concrete worker is pouring the footer for a rectangular house that is 60 ft long and 40 ft wide. The trench dug around the outside edge of the house is 18 inches wide and 30 inch
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Question 317940: A concrete worker is pouring the footer for a rectangular house that is 60 ft long and 40 ft wide. The trench dug around the outside edge of the house is 18 inches wide and 30 inches deep. Find the area of the footer? Please Help me get started! Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! The outside edge is 60 & 40.
The inside edge is (60-2*1.5) & (40-2*1.5).
Thus we have the surface area of:
a=60*40-(60-3)(40-3)
a=2,400-(57*37)
a=2,400-2,109=291 ft^2.
The depth is 30 in. or 2.5 ft.
291*2.5=727.5 ft^3 is the total volume of cement required.
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