SOLUTION: The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in standard form

Algebra ->  Circles -> SOLUTION: The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in standard form      Log On


   

Question 1057749: The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in standard form
Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The midpoint of the line connecting (0,3) and (0,-4) is the center of the circle.
The distance from (0,3) to (0,-4) is the diameter.
x%5Bm%5D=%280%2B0%29%2F2=0
y%5Bm%5D=%283-4%29%2F2=-1%2F2
So then,
D%5E2=%280-0%29%5E2%2B%283-%28-4%29%29%5E2
D=7 so R=7%2F2
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x%5E2%2B%28y%2B1%2F2%29%5E2=49%2F4
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Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!

The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in standard form
Equation of a circle: %28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2

(x, y) = (0, 3)

Midpoint of diameter, or center of circle (h, k) is on the y-axis, at the coordinate point:matrix%281%2C3%2C+%22%280%2C%22%2C+-+1%2F2%2C+%22%29%22%29

matrix%281%2C3%2C+r+=+d%2F2%2C+%22=====%3E%22%2C+r+=+7%2F2%29

Equation of circle: