SOLUTION: i need help and a couple of things explained better if possible this is what my textbook says: By drawing a suitable graph, find the roots of these quadratic functions. Check e

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Question 282540: i need help and a couple of things explained better if possible
this is what my textbook says:
By drawing a suitable graph, find the roots of these quadratic functions. Check each root by substitution:
this is what we have been told to find by our teacher
where does x�-x=0 cut the y-intercept
where it cuts the x-axis
locate the turning point (an axis of symmetry)
i dont know how to do any of it so there is nothing i can write to show what i have done so far ?
thanks if you get back to me x
Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website!
There are some problems with your wording.
x^2-x=0
x*(x-1)=0
the two roots are x=0 and x=1
that is where the parabola crosses the x axis
(0,0) and (1,0)
x intercept is when y =zero the zeroes or roots of the equation
y intercept is when x=0
Nothing cuts the y intercept. Perhaps you want to know the y intercept where x=0 or where it cuts(crosses) the y axis.
1/2^2-1/2
1/4-1/2=-1/4

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1, 0. Here's your graph: