SOLUTION: hello can some one check this for me please? i have to find the x intercepts y=x^2+2x-3 y=0 o=(x+4)(x-2) x=-4 or x=2

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Question 80807: hello can some one check this for me please?
i have to find the x intercepts
y=x^2+2x-3
y=0
o=(x+4)(x-2)
x=-4
or
x=2
Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(48558) About Me  (Show Source):
You can put this solution on YOUR website!
find the x intercepts
y=x^2+2x-3
Let y=0:
x^2+2x-3=0
(x+3)(x-1)=0
x=-3 or x=1
Cheers,
Stan H.
Hint: You did not factor correctly. You can check your factoring
by using FOIL to see if you get the original polynomial when you
do the multiplication.

Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Hmmm...I get something different:
Solve for x:
y+=+x%5E2%2B2x-3 Set y = 0 and solve for the x's.
x%5E2%2B2x-3+=+0 Factor the trinomial.
%28x%2B3%29%28x-1%29+=+0 Apply the zero products principle.
x%2B3+=+0 and/or x-1+=+0
So...
x+=+-3 and x+=+1
A good way to verify this is to look at the graph of the original equation:
graph%28300%2C200%2C-5%2C5%2C-5%2C5%2Cx%5E2%2B2x-3%29
As you can see from the graph, the x-intercepts are:
x = -3 and x = 1