SOLUTION: AHHHH - word problems kill me! Anyone out there willing to help me to see it through? A photo is 3 inches longer than it is wide. A 2-inch border is placed around the photo ma

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Question 59263: AHHHH - word problems kill me! Anyone out there willing to help me to see it through?
A photo is 3 inches longer than it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in^2. What are the dimensions of the photo?
Thank you!
Found 2 solutions by josmiceli, Cintchr:
Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
You've got to get the right picture
width = w
length = w + 3
The 2" border actually adds 4" to the width and 4" to the length.
That's because there's 2" on each side of the photo

complete the square

take square root of both sides

take the square root of both sides

so, it's a 5x8 photo
check

OK

Answer by Cintchr(481) (Show Source):
You can put this solution on YOUR website!
Photo :
Width = x
Length = x + 3

The border adds two inches TO EACH SIDE, so that is 4 more inches to add to the length and width
Photo w/border:

Width = x + 4
Length = x + 7
Area + 108

FOIL

subtract 108 from both sides

factor

set each equal to 0
and
and
Lengths CAN NOT be negative values

Photo :
Width = x = 5
Length = x + 3 = 8