You can
put this solution on YOUR website!a=3x^2+
b=8x+
c=2
----------------------
The a,b,and c are the coefficients of the terms,
not the terms themselves.
a=3
b=8
c=2
----------
Then the determinant is b^2-4ac = 64-4*3*2=40
Since this is greater than zero the quadratic has
two real zeroes. The zeroes may be irrational and
still be real.
Consider the following:
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=40 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: -0.279240779943873, -2.38742588672279.
Here's your graph:
 |
Hope this helps.
Cheers,
Stan H.